document.write( "Question 379335: i really need help with this problem. i'm clueless\r
\n" ); document.write( "\n" ); document.write( "2Y=3X-Xsquared
\n" ); document.write( "X+2Y=-12\r
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Algebra.Com's Answer #269746 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
2Y = 3X - X^2
\n" ); document.write( "X + 2Y = -12
\n" ); document.write( "Let's rearrange it like this
\n" ); document.write( "------>x + 2y = -12
\n" ); document.write( "x^2 - 3x + 2y = 0
\n" ); document.write( "--------------------subtraction eliminates y, and we have
\n" ); document.write( "-x^2 + 4x = -12
\n" ); document.write( "Multiply by -1,
\n" ); document.write( "x^2 - 4x = 12
\n" ); document.write( "x^2 - 4x - 12 = 0; a quadratic equation
\n" ); document.write( "Factors to:
\n" ); document.write( "(x-6)(x+2) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 6
\n" ); document.write( "x = -2
\n" ); document.write( ":
\n" ); document.write( "Use the 1st original equation to find y, using x=6
\n" ); document.write( "2Y = 3X - X^2
\n" ); document.write( "2Y = 3(6) - 6^2
\n" ); document.write( "2y = 18 - 36
\n" ); document.write( "2y = -18
\n" ); document.write( "y = $\"%28-18%29%2F2\"$
\n" ); document.write( "y = -9
\n" ); document.write( ":
\n" ); document.write( "1st solution: x=6; y=-9
\n" ); document.write( ":
\n" ); document.write( "Check this in the original 2nd equation
\n" ); document.write( "X + 2Y = -12
\n" ); document.write( "6 + 2(-9) = -12; confirms this solution
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "What about x = -2
\n" ); document.write( "Use the 1st original equation to find y, using x=-2
\n" ); document.write( "2Y = 3X - X^2
\n" ); document.write( "2Y = 3(-2) - (-2^2)
\n" ); document.write( "2y = -6 - 4
\n" ); document.write( "2y = -10
\n" ); document.write( "y = $\"%28-10%29%2F2\"$
\n" ); document.write( "y = -5
\n" ); document.write( ":
\n" ); document.write( "2nd solution x =-2; y = -5
\n" ); document.write( ":
\n" ); document.write( "Check this in the original 2nd equation
\n" ); document.write( "X + 2Y = -12
\n" ); document.write( "-2 + 2(-5) = -12; confirms this solution also
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Did this provide a clue or two for you, did it make sense? \n" ); document.write( "

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