document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=379945>Question 379945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose the width of 4 inches is decreased by 3 inches. Find the percent of change in the perimeter. the rectangle is 6 inches by 4 inches. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269699 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The original perimeter is P = 2(6 + 4) = 2*10 = 20.  If the width is decreased by 3, inches, the new perimeter is 2(6 + 1) = 2*7 = 14.  The percent change is then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2814+-+20%29%2F20 ALIGN=MIDDLE  ALT=\"%2814+-+20%29%2F20\"   DISABLED_style= \"max-width:90%; height:auto;\" >*100% = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-6%2F20 ALIGN=MIDDLE  ALT=\"-6%2F20\"   DISABLED_style= \"max-width:90%; height:auto;\" >*100%, or -30%. </SPAN>\n" );
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