document.write( "Question 379858: Having trouble with a logarithm! I am okay with logarithms, but this one throws in a square root so I am lost as to what to do with it.\r
\n" ); document.write( "\n" ); document.write( "log base-2 (log base-b (sqrt b)) , where b > 0.\r
\n" ); document.write( "\n" ); document.write( "I just had a thought.. do I need to turn sqrt b into b^(1/2)?\r
\n" ); document.write( "\n" ); document.write( "Any help would be appreciated, thanks! :)
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Algebra.Com's Answer #269695 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"log%282%2C+%28log%28b%2C+%28sqrt%28b%29%29%29%29%29\"
\n" ); document.write( "You are correct. start by rewriting \"sqrt%28b%29\" as \"b%5E%281%2F2%29\":
\n" ); document.write( "\"log%282%2C+%28log%28b%2C+%28b%5E%281%2F2%29%29%29%29%29\"
\n" ); document.write( "Next, on the inner logarithm, we can use a property of logarithms, \"log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29\", to \"move\" the exponent of the argument out in front of the logarithm:
\n" ); document.write( "\"log%282%2C+%28%281%2F2%29%2Alog%28b%2C+%28b%29%29%29%29\"
\n" ); document.write( "By definition, \"log%28b%2C+%28b%29%29+=+1\" so this becomes:
\n" ); document.write( "\"log%282%2C+%281%2F2%29%29\"
\n" ); document.write( "The quick way to finish requires that we understand what this expression represents. It represents the exponent for 2 that results in 1/2. If you also understand exponents, you will know that the answer is: -1!

\n" ); document.write( "The long way is to use another property of logarithms, \"log%28a%2C+%28p%2Fq%29%29+=+log%28a%2C+%28p%29%29+-+log%28a%2C+%28q%29%29\", to split the numerator and denominator into separate logarithms:
\n" ); document.write( "\"log%282%2C+%281%29%29+-+log%282%2C+%282%29%29\"
\n" ); document.write( "The logarithm of 1, regardless of the base, is zero (because any number to the zero power is 1). And by definition \"log%282%2C+%282%29%29+=+1\". So now we have:
\n" ); document.write( "0 - 1
\n" ); document.write( "which equals
\n" ); document.write( "-1
\n" ); document.write( "
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