document.write( "Question 379858: Having trouble with a logarithm! I am okay with logarithms, but this one throws in a square root so I am lost as to what to do with it.\r
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document.write( "log base-2 (log base-b (sqrt b)) , where b > 0.\r
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document.write( "I just had a thought.. do I need to turn sqrt b into b^(1/2)?\r
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document.write( "Any help would be appreciated, thanks! :) \n" );
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Algebra.Com's Answer #269695 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You are correct. start by rewriting \n" ); document.write( " \n" ); document.write( "Next, on the inner logarithm, we can use a property of logarithms, \n" ); document.write( " \n" ); document.write( "By definition, \n" ); document.write( " \n" ); document.write( "The quick way to finish requires that we understand what this expression represents. It represents the exponent for 2 that results in 1/2. If you also understand exponents, you will know that the answer is: -1! \n" ); document.write( "The long way is to use another property of logarithms, \n" ); document.write( " \n" ); document.write( "The logarithm of 1, regardless of the base, is zero (because any number to the zero power is 1). And by definition \n" ); document.write( "0 - 1 \n" ); document.write( "which equals \n" ); document.write( "-1 \n" ); document.write( " |