document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=379729>Question 379729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an unbiased coin is tossed 5 times. find the probobility that , there are exactly 4 heads </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269610 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 coin flips can come up a total of 2^5, or 32 different ways.  Only five of those 32 ways have exactly 4 heads...the answer is 5/32.<BR>\n" );
document.write( "The proper way is to look at <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%21+%2F%28%284%21%29%281%21%29%29 ALIGN=MIDDLE  ALT=\"5%21+%2F%28%284%21%29%281%21%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > which equals 5. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );