document.write( "Question 379732: 2logX-log(8x-160)-1=0 \n" ); document.write( "

Algebra.Com's Answer #269609 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "2logX-log(8x-160)-1=0
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document.write( "log(x^2/8(x - 20)=1
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document.write( "10^1  = (x^2/8(x - 20)
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document.write( "10*8(x-20) = x^2
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document.write( "80x - 1600 = x^2
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document.write( "x^2 -80x + 1600 = 0
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document.write( "(x-40)(x-40)=0
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document.write( "x = 40\r
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