document.write( "Question 379726: Graph\r
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Algebra.Com's Answer #269593 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "Hi
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document.write( "the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
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document.write( "y= -1/3(x+6)^2+3  
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document.write( "vertex is Pt(-6,3) negative 'a' of -(1/3) tells us the parabola opens downward
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document.write( "y intercept (when x = 0)
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document.write( "y = -1/3(6)^2 + 3
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document.write( "y = -12 + 3 = -9  Pt(0,-9)
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document.write( "x intercepts (when y = 0)
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document.write( "0 = -1/3(x+6)^2+3  
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document.write( "0 = -(x+6)^2 + 9
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document.write( "(x+6)^2 = 9
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document.write( "(x+6) = ±3
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document.write( "x +6 = 3    x = -3  Pt(-3,0)
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document.write( "x +6 = -3   x = -9  Pt(-9,0)
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