document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=379651>Question 379651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joan can shovel a certain driveway in 50 minutes.  If mary can shovel the same driveway in 20 minutes, how long will it take them, to the nearest minute, to shove the driveway if they work together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269576 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joan can shovel a certain driveway in 50 minutes.  If mary can shovel the same driveway in 20 minutes, how long will it take them, to the nearest minute, to shove the driveway if they work together?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = time (minutes) it takes for both<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x(1/50 + 1/20) = 1<BR>\n" );
document.write( "multiplying both sides by 1000:<BR>\n" );
document.write( "x(20 + 50) = 1000<BR>\n" );
document.write( "x(70) = 1000<BR>\n" );
document.write( "x = 14.29<BR>\n" );
document.write( "rounded:<BR>\n" );
document.write( "x = 14 minutes<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );