document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=379528>Question 379528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mechanic requires 3 h to repair a transmission, whereas an apprentice requires 9 h to make the same repairs. The mechanic worked alone for 1.5 h and then stopped.\r<BR>\n" );
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document.write( "how long will it take the apprentice, working alone, to complete the repairs? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269472 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of time it takes the apprentice, working alone, to complete the repairs<BR>\n" );
document.write( "The mechanic works at the rate of 1/3 transmission per hour<BR>\n" );
document.write( "The apprentice works at the rate of 1/9 transmission per hour\r<BR>\n" );
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document.write( "In 1.5 hours, the mechanic completes (1/3)*1.5  or 1/2 of the job, leaving 1/2 of the job yet to be done. So we have to calculate the following:<BR>\n" );
document.write( "(1/9 transmission per hour)* x hours=(1/2 transmission); or<BR>\n" );
document.write( "(1/9)x=1/2  multiply each side by 18<BR>\n" );
document.write( "2x=9<BR>\n" );
document.write( "x=4.5 hours---time required for the apprentice to finish the job\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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