document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378919>Question 378919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An electric radiator which is an ordinary constant resistor emits a heating power of 1.2 KW at a mains supply voltage of 230 V. <BR>\n" );
document.write( "what is the total heating power in each respective instance when two such radiators are connected<BR>\n" );
document.write( "a) in parallel, and <BR>\n" );
document.write( "b) in series to the 230 V supply voltage ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269462 by </B><A HREF=/tutors/aboutme.mpl?userid=rfadrogane><B>rfadrogane(214)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfadrogane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rfadrogane><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An electric radiator which is an ordinary constant resistor emits a heating power of 1.2 KW at a mains supply voltage of 230 V. <BR>\n" );
document.write( "what is the total heating power in each respective instance when two such radiators are connected<BR>\n" );
document.write( "a) in parallel, and <BR>\n" );
document.write( "b) in series to the 230 V supply voltage ?\r<BR>\n" );
document.write( "\n" );
document.write( "Try to clarify your 230-V, its an AC or DC?, if AC, then state the frequency\r<BR>\n" );
document.write( "\n" );
document.write( "Assuming that the radiator is a non-inductive load,<BR>\n" );
document.write( " let us solve first the resistance of the radiator<BR>\n" );
document.write( "  from: P = E^2/R<BR>\n" );
document.write( "        R = E^2/P, E = 230-V & P = 1,200-W<BR>\n" );
document.write( "          = (230)^2/1,200<BR>\n" );
document.write( "        R = 44.083-ohms<BR>\n" );
document.write( "a) when parallel,the total power is the summation of its rating, thus it is<BR>\n" );
document.write( "    Pt = 1,200W + 1,200W = 2,400W ----answer<BR>\n" );
document.write( "b) when series,the total power is the summation of its rating, thus it is<BR>\n" );
document.write( "    Pt = 1,200W + 1,200W = 2,400W ----answer<BR>\n" );
document.write( "   <BR>\n" );
document.write( "             </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );