document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=379525>Question 379525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a carnival game a single die is rolled.  If the number that shows on top is odd, you win that amount.  If the number showing on top is even, you lose that amount.  Construct a probability distribution for this game and find the expected value for a person playing this game.\r<BR>\n" );
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document.write( "I have done a few of these, but this one throws me.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269458 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X be the random variable representing the earnings/loss at a single throw.  Then X = 1,3,5,-2,-4,-6.  We get the following discrete uniform probability mass function:<BR>\n" );
document.write( "P(1) = P(2) =P(3) = P(-2) = P(-4) = P(-6) = 1/6.<BR>\n" );
document.write( "The expected value is then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=mu+=+%281%2B3%2B5%29%281%2F6%29+%2B+%28-2-4-6%29%281%2F6%29+=+9%2F6+-+12%2F6+=+-1%2F2+=+-0.50 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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