document.write( "Question 41768: 27^3n-1 = 81^ -n \n" ); document.write( "
Algebra.Com's Answer #26942 by longjonsilver(2297)\"\" \"About 
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Assuming you mean \"+27%5E%283n-1%29+=+81%5E%28-n%29+\"\r
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\n" ); document.write( "\n" ); document.write( "then we get \"+3%5E3%5E%283n-1%29+=+3%5E4%5E%28-n%29+\"
\n" ); document.write( "\"+3%5E%283%283n-1%29%29+=+3%5E%28-4n%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and so we have 3 raised to a power on both sides of the equal sign, so the 2 powers must be the same.\r
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\n" ); document.write( "\n" ); document.write( "--> 3(3n-1) = -4n
\n" ); document.write( "9n-3 = -4n
\n" ); document.write( "13n = 3
\n" ); document.write( "n = 3/13\r
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\n" ); document.write( "\n" ); document.write( "CHECK:
\n" ); document.write( "3n-1 is -4/13
\n" ); document.write( "-n is -3/13\r
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\n" ); document.write( "\n" ); document.write( "so work out if \"+27%5E%28-4%2F13%29+\" is the same as \"+81%5E%28-3%2F13%29+\". Both come to the same decimal.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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