document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=379432>Question 379432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lenghth is 3 yd. more than twice the width. the perimeter is 36 yd. what are the length and widths </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269416 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the perimeter be P.  It equals 36.  <BR>\n" );
document.write( "Let W be width and L be length.  So<BR>\n" );
document.write( "P = 2L + 2W = 36<BR>\n" );
document.write( "Now the other statement can be written as<BR>\n" );
document.write( "L = 3 + 2W<BR>\n" );
document.write( "Now substitute this into the first equation and get<BR>\n" );
document.write( "2(3 + 2W) + 2W = 36<BR>\n" );
document.write( "6 + 4W + 2W = 36<BR>\n" );
document.write( "6 + 6W = 36<BR>\n" );
document.write( "6W = 30<BR>\n" );
document.write( "W = 5<BR>\n" );
document.write( "and L = L = 3 + 2W = 3 + 2(5) = 13<BR>\n" );
document.write( " </SPAN>\n" );
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