document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=379327>Question 379327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is two more than a second number. Twice the first is 4 less than 3 times the second. Find the numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269323 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is two more than a second number. Twice the first is 4 less than 3 times the second. Find the numbers.\r<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "x = y+2<BR>\n" );
document.write( "2x= 3y-4<BR>\n" );
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document.write( "Substitute for x and solve for \"y\":<BR>\n" );
document.write( "2(y+2) = 3y-4<BR>\n" );
document.write( "2y+4 = 3y-4<BR>\n" );
document.write( "y = 8 (the 2nd number)<BR>\n" );
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document.write( "Since x = y + 2, x = 10 (the 1st number)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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