document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378593>Question 378593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me with this                                                                              define avariable write an equation and solve each problem:one half of a number decreased by two thirds is two less than one fifth of the number find the number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269307 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = \"the number\"<BR>\n" );
document.write( ": <BR>\n" );
document.write( "Write an equation just as it says:<BR>\n" );
document.write( "\"one half of a number decreased by two thirds is two less than one fifth<BR>\n" );
document.write( " of the number find the number<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >x - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F5 ALIGN=MIDDLE  ALT=\"1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >x - 2<BR>\n" );
document.write( "If we multiply equation by 30, we can get rid of those annoying fractions, results:<BR>\n" );
document.write( "15x - 20 = 6x - 30(2) <BR>\n" );
document.write( "15x = 6x - 60 + 20<BR>\n" );
document.write( "15x - 6x = -60 + 20<BR>\n" );
document.write( "9x = -40<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-40%29%2F9 ALIGN=MIDDLE  ALT=\"%28-40%29%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = -4.44, a rather disappointing number, see if it works in the original equation<BR>\n" );
document.write( ":<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(-4.44) - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F5 ALIGN=MIDDLE  ALT=\"1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >(-4.44) - 2<BR>\n" );
document.write( "-2.22 - .67 = -.89 - 2<BR>\n" );
document.write( "-2.89 = -2.89; so I guess x = -4.44 is the solutions\r<BR>\n" );
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