document.write( "Question 41720: Log5 1/625. the question asks evaluate the logarithm. \n" ); document.write( "

Algebra.Com's Answer #26924 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%285%2C+1%2F625%29+=+x\"$
\n" ); document.write( "rewrite this as
\n" ); document.write( " $\"1%2F625+=+5%5Ex\"$
\n" ); document.write( "multiply both sides by 625
\n" ); document.write( " $\"1+=+5%5Ex+%2A+625\"$
\n" ); document.write( " $\"625+=+5%5E4\"$
\n" ); document.write( " $\"1+=+5%5Ex%2A5%5E4\"$
\n" ); document.write( " $\"1+=+5%5E%28x+%2B+4%29\"$
\n" ); document.write( "anything to the zero power is 1
\n" ); document.write( "If x = -4, then
\n" ); document.write( " $\"1+=+5%5E%28-4+%2B4%29\"$
\n" ); document.write( "This is an identity
\n" ); document.write( "check
\n" ); document.write( " $\"1%2F625+=+5%5Ex\"$
\n" ); document.write( " $\"1%2F625+=+5%5E%28-4%29\"$
\n" ); document.write( " $\"1%2F%285%5E4%29+=+5%5E%28-4%29\"$
\n" ); document.write( " $\"5%5E%28-4%29+=+5%5E%28-4%29\"$
\n" ); document.write( "OK \n" ); document.write( "

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