document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41619>Question 41619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the Intermediate Value Theorem to show that the graph of the function has a zero in the given interval.  Round the zero to two decimal places.<BR>\n" );
document.write( "	f(x) = 2x3 + x2 – x – 5;  [1, 2] Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26915 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the Intermediate Value Theorem to show that the graph of the function has a zero in the given interval. Round the zero to two decimal places.<BR>\n" );
document.write( "f(x) = 2x3 + x2 – x – 5; [1, 2] Please help<BR>\n" );
document.write( "F(1)=2+1-1-5=-3<BR>\n" );
document.write( "F(2)=2*2^3+2^2-2-5=16+4-2-5=13<BR>\n" );
document.write( "F(X) IS CONTINUOUS IN THIS RANGE AND CHANGES ITS SIGN FROM -VE TO +VE.HENCE IT HAS ZERO IN THIS RANGE<BR>\n" );
document.write( "NARROWING THE RANGE TO GET AT THE ZERO..TRY X=(1+2)/2=1.5<BR>\n" );
document.write( "F(1.5)=2.5..<BR>\n" );
document.write( "THEN...TRY...(1+1.5)/2=1.25 ..F(1.25)=-0.78<BR>\n" );
document.write( "THEN ..TRY....(1.25+1.5)/2=1.375....F(1.375)=0.714.......ETC..\r<BR>\n" );
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document.write( "WE FIND BY TRIAL THAT  AT X=1.32 F(X)=0 </SPAN>\n" );
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