document.write( "Question 378936: can you please help me with this problem\r
\n" ); document.write( "\n" ); document.write( "same direction:
\n" ); document.write( "a truck left the terminal traveling 50mi/h.
\n" ); document.write( "a heavier truck traveled at 60mph. it left 2 hours later.
\n" ); document.write( "they both follow the same route.
\n" ); document.write( "how many hours will it take truck #1 to catch up with truck #2
\n" ); document.write( "

Algebra.Com's Answer #269125 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "D = r*t This question sets up that the distance traveled is the same for each.
\n" ); document.write( "Question states: truck traveling at 60mph...left 2 hours later
\n" ); document.write( "Let (t + 2)and t represent the respective times traveled by the trucks
\n" ); document.write( "50mph(t+2) = 60mph*t
\n" ); document.write( "solving for t
\n" ); document.write( "50t + 100 = 60t
\n" ); document.write( "100 = 10t
\n" ); document.write( "10hr = t, time it will take for the truck traveling 60mph to catch up
\n" ); document.write( "CHECKING OUR ANSER
\n" ); document.write( "50mph*12hr = 60mph*10hr = 600mi (misc info as to the distance traveled by each) \n" ); document.write( "
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