document.write( "Question 378930: A body is thrown vertically upward from the distance h = 1.5 m above the ground at the edge of a pit having a depth of s = 3.5 m
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document.write( "The initial velocity of body is 2.3 m/s
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document.write( "Determine the velocity at which the body will reach the bottom of the pit. \n" );
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Algebra.Com's Answer #269123 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! You didn't give the info, so I'll assume this is on the Earth and use \n" ); document.write( "h(t) = -4.9t^2 + vt, t in seconds, h in meters \n" ); document.write( "------------------- \n" ); document.write( "h(t) = -16t^2 + 2.3t \n" ); document.write( "Find t for h(t) = -3.5 meters \n" ); document.write( "-3.5 = -4.9t^2 + 2.3t \n" ); document.write( "-4.9t^2 + 2.3t + 3.5 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---------------- \n" ); document.write( "t = 1.1118 seconds (Ignore the negative solution) \n" ); document.write( "velocity = h'(t) = -9.8t + 2.3 \n" ); document.write( "h'(1.1118) = -8.59564 m/sec at impact (negative = going down)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |