document.write( "Question 378786: please help me solve this problem: a square poster has two sides measuring 2 ft less than the sides of a square sign. if the difference between their areas is 36sq feet, find the lengths of the sides of the poster and the sign. \n" ); document.write( "
Algebra.Com's Answer #269033 by mananth(16946)\"\" \"About 
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let side of square sign be x
\n" ); document.write( "area = x^2
\n" ); document.write( "..
\n" ); document.write( "square poster side = (x-2)
\n" ); document.write( "area = (x-2)^2
\n" ); document.write( "..
\n" ); document.write( "x^2-(x-2)^2= 36
\n" ); document.write( "x^2-(x^2-4x+4)=36
\n" ); document.write( "x^2-x^2+4x-4=36
\n" ); document.write( "4x-4=36
\n" ); document.write( "+4
\n" ); document.write( "4x-4+4 = 36+4
\n" ); document.write( "4x=40
\n" ); document.write( "/4
\n" ); document.write( "x= 10 feet. side of sign
\n" ); document.write( "10-2=8 feet = side of poster
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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