document.write( "Question 378786: please help me solve this problem: a square poster has two sides measuring 2 ft less than the sides of a square sign. if the difference between their areas is 36sq feet, find the lengths of the sides of the poster and the sign. \n" ); document.write( "
Algebra.Com's Answer #269033 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let side of square sign be x \n" ); document.write( "area = x^2 \n" ); document.write( ".. \n" ); document.write( "square poster side = (x-2) \n" ); document.write( "area = (x-2)^2 \n" ); document.write( ".. \n" ); document.write( "x^2-(x-2)^2= 36 \n" ); document.write( "x^2-(x^2-4x+4)=36 \n" ); document.write( "x^2-x^2+4x-4=36 \n" ); document.write( "4x-4=36 \n" ); document.write( "+4 \n" ); document.write( "4x-4+4 = 36+4 \n" ); document.write( "4x=40 \n" ); document.write( "/4 \n" ); document.write( "x= 10 feet. side of sign \n" ); document.write( "10-2=8 feet = side of poster \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |