document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378758>Question 378758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a number such that if 3 times the number is decreased by 15 the result is twice the opposite of the number, </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269020 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269020\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-15=-2x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "3x+2x=15\r<BR>\n" );
document.write( "\n" );
document.write( "5x=15\r<BR>\n" );
document.write( "\n" );
document.write( "x=3\r<BR>\n" );
document.write( "\n" );
document.write( "number is 3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );