document.write( "Question 378435: First i need to explain the drawings i have been given. I was given a triangle and a square. On each of the three sides of the triangle there is x-y, and on each side of the square there is just y. So adding (x-y)+(x-y)+(x-y) would give you the permiter of the triangle, and adding the 4 ys would give you the permiter of the square. Now the question is,the perimters of the square and the triangle are equal. Find (x,y) if three times the perimter of the square exceeds twice the perimter of the triangle by 24. \n" ); document.write( "

Algebra.Com's Answer #269012 by scott8148(6628) $\"\"$ $\"About$

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\"the perimters of the square and the triangle are equal\" ___ 4y = 3(x-y)\r
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\n" ); document.write( "\n" ); document.write( "\"three times the perimter of the square exceeds twice the perimter of the triangle by 24\" ___ 3(4y) = 2[3(x-y)] + 24\r
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\n" ); document.write( "\n" ); document.write( "use substitution to find y ___ substitute 4y for 3(x-y) (in the 2nd equation)\r
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\n" ); document.write( "\n" ); document.write( "then use the value of y to find the value of x (in the 1st equation) \n" ); document.write( "

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