document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=815>Question 815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the compliment of an angle is one tenth the supplement of the angle than what is the measure of the angle? I am unsure where to start..... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269 by </B><A HREF=/tutors/aboutme.mpl?userid=pushpaharan><B>pushpaharan(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pushpaharan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angle be x.<BR>\n" );
document.write( "therefore complement angle to x = 90-x<BR>\n" );
document.write( "supplement angle = 180-x<BR>\n" );
document.write( "but compliment of an angle is one tenth the supplement of the angle \r<BR>\n" );
document.write( "\n" );
document.write( "90-x = 1/10(180-x)<BR>\n" );
document.write( "10(90-x) = (180-x)<BR>\n" );
document.write( "900-10x = 180- x<BR>\n" );
document.write( "-10x + x = 180-900<BR>\n" );
document.write( "-9x = -720<BR>\n" );
document.write( "x=80\r<BR>\n" );
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document.write( "Hope you got it.:-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );