document.write( "Question 378601: The sum of two numbers is 47. One number is 5 more than twice the other number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #268982 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! x + y = 47 \n" ); document.write( "x = 2y + 5 \n" ); document.write( "sub for x in eqn 1 \n" ); document.write( "(2y+5) + y = 47 \n" ); document.write( "3y+5 = 47 \n" ); document.write( "3y = 42 \n" ); document.write( "y = 14 \n" ); document.write( "the other number = 33 \n" ); document.write( " \n" ); document.write( " |