document.write( "Question 378601: The sum of two numbers is 47. One number is 5 more than twice the other number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #268982 by Alan3354(69443)\"\" \"About 
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x + y = 47
\n" ); document.write( "x = 2y + 5
\n" ); document.write( "sub for x in eqn 1
\n" ); document.write( "(2y+5) + y = 47
\n" ); document.write( "3y+5 = 47
\n" ); document.write( "3y = 42
\n" ); document.write( "y = 14
\n" ); document.write( "the other number = 33
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