document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378695>Question 378695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having a really hard time remembering how to solve this type of question:\r<BR>\n" );
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document.write( "sin(theta) = 6/7<BR>\n" );
document.write( "theta is between 90 and 180 degrees.\r<BR>\n" );
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document.write( "Find the remaining trig functions.\r<BR>\n" );
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document.write( "I can get cosine, but after that, I'm lost. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268973 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From sin(theta) = 6/7, we take the inverse sine (call it arcsin) of both sides and get<BR>\n" );
document.write( "theta = arcsin (6/7)<BR>\n" );
document.write( "Be careful that the angle theta is a second quadrant angle...180 - theta gives it to you...<BR>\n" );
document.write( "Once you know cos(theta), which you said you already have, finding the rest is like this...<BR>\n" );
document.write( "tan x = sin x / cos x<BR>\n" );
document.write( "cot x = cos x / sin x<BR>\n" );
document.write( "csc x = 1 / sin x<BR>\n" );
document.write( "sec x = 1 /cos x<BR>\n" );
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