document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41609>Question 41609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> it tell you to use the substitution method to solve the linear system\r<BR>\n" );
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document.write( "x +2y = - 5<BR>\n" );
document.write( "4x-3y=2\r<BR>\n" );
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document.write( "3x-2y=4<BR>\n" );
document.write( "x+3y=5\r<BR>\n" );
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document.write( "3x+y= -2<BR>\n" );
document.write( "x+3y=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26895 by </B><A HREF=/tutors/aboutme.mpl?userid=K+N+Swamy><B>K N Swamy(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=K+N+Swamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> q1.<BR>\n" );
document.write( "x+2y=-5----(1)<BR>\n" );
document.write( "4x-3y=2---(2)<BR>\n" );
document.write( "from (1), X=-2Y-5<BR>\n" );
document.write( "substitute x=-2y-5 in (2)<BR>\n" );
document.write( "4(-2y-5)-3y=2<BR>\n" );
document.write( "-8y-20-3y=2<BR>\n" );
document.write( "-11y-20=2<BR>\n" );
document.write( "-11y=-22<BR>\n" );
document.write( "y=-22/-11<BR>\n" );
document.write( "y=2<BR>\n" );
document.write( "x=-2y-5<BR>\n" );
document.write( "substitute y=2<BR>\n" );
document.write( "x=-2(2)-5<BR>\n" );
document.write( "x=-4-5<BR>\n" );
document.write( "x=-9<BR>\n" );
document.write( "Hence x=-9 and y=2 </SPAN>\n" );
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