document.write( "Question 378651: A right triangle has sides measuring 2x-1, 3x-13, and 3x-4 units. What is the value of x? \n" ); document.write( "
Algebra.Com's Answer #268930 by stanbon(75887)\"\" \"About 
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A right triangle has sides measuring 2x-1, 3x-13, and 3x-4 units. What is the value of x?
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\n" ); document.write( "longest side: 3x-4
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\n" ); document.write( "Equation:
\n" ); document.write( "(2x-1)^2 + (3x-13)^2 = (3x-4)^2
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\n" ); document.write( "4x^2-4x+1 + 9x^2-78x+169 = 9x^2-24x+16
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\n" ); document.write( "13x^2-82x+170 = 9x^2-24x+16
\n" ); document.write( "4x^2 - 58x + 154 = 0
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\n" ); document.write( "2x^2 - 29x + 77 = 0
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\n" ); document.write( "Positive Solution:
\n" ); document.write( "x = [29 +- sqrt(29^2 - 4*2*77)]/4
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\n" ); document.write( "x = [29 +- sqrt(225)]/4
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\n" ); document.write( "x = [29+-15]/4
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\n" ); document.write( "x = 11 or x = 7/2
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\n" ); document.write( "Only x=11 is a viable answer to get positive side lengths.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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