document.write( "Question 378637: The width of a rectangle is 55 cm less than three times its length. The area of the rectangle is 100 cm^2. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #268927 by richard1234(7193)\"\" \"About 
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Suppose the length of the rectangle is x cm. Then the width is 3x - 55.\r
\n" ); document.write( "\n" ); document.write( "Now, we have\r
\n" ); document.write( "\n" ); document.write( "\"x%283x+-+55%29+=+100\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%5E2+-+55x+-+100+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Luckily, this factors to (3x + 5)(x - 20) = 0, so either x = -5/3 or x = 20. We take the positive value, so the length is 20 and the width is 5.
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