document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378613>Question 378613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is the square root of 13cm. One leg is 1 cm shorter then twice the length of the other leg. Find the lengths of the legs of the right triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268914 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the length of one leg be x cm<BR>\n" );
document.write( "the other leg  = 2x-1 cm<BR>\n" );
document.write( "Hypotenuse = sqrt(13)<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x^2+(2x-1)^2=(13)<BR>\n" );
document.write( "x^2+4x^2-4x+1=13<BR>\n" );
document.write( "5x^2-4x+1-13<BR>\n" );
document.write( "5x^2-4x-12=0<BR>\n" );
document.write( "5x^2-10x+6x-12=0<BR>\n" );
document.write( "5x(x-2)+6(x-2)=0<BR>\n" );
document.write( "(x-2)(5x+6)=0<BR>\n" );
document.write( "x= 2 <BR>\n" );
document.write( "...<BR>\n" );
document.write( "length of one leg = 2cm<BR>\n" );
document.write( "other leg = 2x-1 = 3 cm<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );