document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378574>Question 378574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive interges such that the sum of twice the smalles and 3 times the largest is 126 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268895 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = smallest integer<BR>\n" );
document.write( "x+1 = middle integer<BR>\n" );
document.write( "x+2= largest integer\r<BR>\n" );
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document.write( "The equation is in the sentence \"the sum of twice the smallest and 3 times the largest is 126\".  Translated, this means\r<BR>\n" );
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document.write( "2(    )   +   3(       ) = 126<BR>\n" );
document.write( "2(x) + 3(x+2)=126<BR>\n" );
document.write( "2x + 3x+6 = 126<BR>\n" );
document.write( "5x+6=126<BR>\n" );
document.write( "5x=120<BR>\n" );
document.write( "x=120/5=24 smallest<BR>\n" );
document.write( "x+1=25  middle<BR>\n" );
document.write( "x+2=26  largest\r<BR>\n" );
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document.write( "Check:  \r<BR>\n" );
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document.write( "2*24 + 3*26 <BR>\n" );
document.write( "48 + 78<BR>\n" );
document.write( "126\r<BR>\n" );
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document.write( "It checks!!\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired<BR>\n" );
document.write( "Seminole State College of Florida<BR>\n" );
document.write( "Altamonte Springs Campus  </SPAN>\n" );
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