document.write( "Question 378561: The radioactive element americium-241 has half the life of 432 years. Suppose we start with a 45-g mass of americium-241, how much would be left after 343 years? \n" ); document.write( "
Algebra.Com's Answer #268892 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! The formula for determining the amount of substance left is \n" ); document.write( "\n" ); document.write( "Given the half-life of 432 years, we may plug in t:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Taking ln of both sides,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, we substitute t = 343 years to our equation to obtain\r \n" ); document.write( "\n" ); document.write( " |