document.write( "Question 378469: On this problem: A photo is 10 cm longer than it is wide. It is mounted in a frame 2 cm wide. The area of the frame is 112cm squared. Find the dimensions of the photo. \ I have no idea even where to start! \n" ); document.write( "
Algebra.Com's Answer #268862 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the width of the photo. Then the length of the photo must be . Since the frame is 2 cm wide, it adds 2 cm to EACH side, top, and bottom. So the overall width, including the frame, must be cm, and the overall length must be cm. The area of a rectangle is the length times the width:\r
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\n" ); document.write( "\n" ); document.write( "Solve the quadratic, exclude the negative root, and the positive root is the width of the photo. Note: This ugly beast does NOT factor. You need to haul out the quadratic formula. And this is one really odd shaped photo.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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