document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378447>Question 378447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Aunt karen is eight years younger thank twice the age of Mary. Their ages add up to twenty-eight. Find the age of Aunt Karen and Mary. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268859 by </B><A HREF=/tutors/aboutme.mpl?userid=sophxmai><B>sophxmai(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sophxmai><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sophxmai><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let k stand for Karen's age, and m stand for Mary's age.\r<BR>\n" );
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document.write( "2m-8=k<BR>\n" );
document.write( "k+m=28\r<BR>\n" );
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document.write( "Substitute k for k=2m-8<BR>\n" );
document.write( "(2m-8)+m=28<BR>\n" );
document.write( "3m-8=28<BR>\n" );
document.write( "3m=36<BR>\n" );
document.write( "m=12\r<BR>\n" );
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document.write( "Substitute m for m=12<BR>\n" );
document.write( "k+m=28<BR>\n" );
document.write( "k+(12)=28<BR>\n" );
document.write( "k=16\r<BR>\n" );
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document.write( "Karen is 16 years old, Mary is 12 years old. </SPAN>\n" );
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