document.write( "Question 378434: the larger of two numbers is 9 more than twice the smaller. the sum of the numbers is 3 less than five times the smaller. find the number.\r
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document.write( "show work please. \n" );
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Algebra.Com's Answer #268854 by sophxmai(62) You can put this solution on YOUR website! Let x be the smaller number and y be the larger number. \n" ); document.write( "y=2x+9 \n" ); document.write( "x+y=5x-3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute y=2x+9 for y. \n" ); document.write( "x+(2x+9)=5x-3 \n" ); document.write( "3x+9=5x-3 \n" ); document.write( "12=2x \n" ); document.write( "6=x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If x is 6, then y is ? \n" ); document.write( "y=2x+9 \n" ); document.write( "y=2(6)+9 \n" ); document.write( "y=12+9 \n" ); document.write( "y=21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When x is 6, y is 21. \n" ); document.write( "The two numbers are 6 and 21. \n" ); document.write( " |