document.write( "Question 41614: I have a problem that I think has no solution. Is this right?\r
\n" ); document.write( "\n" ); document.write( "(sqrt2x+6)+6=0\r
\n" ); document.write( "\n" ); document.write( "I got 2x+6=12
\n" ); document.write( "2x=18
\n" ); document.write( "I do not see a solution. Am I doing something wrong?
\n" ); document.write( "

Algebra.Com's Answer #26885 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let's see...
\n" ); document.write( "\"sqrt%282x%2B6%29+%2B+6+=+0\" Subtract 6 from both sides.
\n" ); document.write( "\"sqrt%282x%2B6%29+=+-6\" Now square both sides.
\n" ); document.write( "\"2x%2B6+=+36\" Subtract 6 from both sides.
\n" ); document.write( "\"2x+=+30\" Divide both sides by 2.
\n" ); document.write( "\"x+=+15\"
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