document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378309>Question 378309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to company reports, the current mix of colors for M&M dark chocolate candies is:  20% yellow, 10% red, 15% orange, 10% blue, 25% green, with the rest being brown.  <BR>\n" );
document.write( "A.  If a single piece is taken from a bag of 600 pieces, find the following probabilities:<BR>\n" );
document.write( "a.  P (red)<BR>\n" );
document.write( "b.  P (brown)<BR>\n" );
document.write( "c.  P (blue or orange)<BR>\n" );
document.write( "d.  P (NOT red)		<BR>\n" );
document.write( "e. P (NOT brown)<BR>\n" );
document.write( "f.  P (red and green)\r<BR>\n" );
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document.write( "B.  If two pieces are taken from a 600 piece bag, find the following probabilities:<BR>\n" );
document.write( "a.  P (both are blue)		<BR>\n" );
document.write( "b.  P (the first is orange)			<BR>\n" );
document.write( "c.  P (first is red and the second is green)\r<BR>\n" );
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document.write( "C.  How would the process in problem #1A change if we are sampling from a “fun-size” bag which only has 12 pieces?\r<BR>\n" );
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document.write( "D.  How would the process in problem #1B change if we are sampling from a “fun-size” bag which only has 12 pieces?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268816 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 100-20-10-15-10-25=20% are brown<BR>\n" );
document.write( "600*.2=120 yellow<BR>\n" );
document.write( "600*.1= 60 red<BR>\n" );
document.write( "600*.15=90 orange<BR>\n" );
document.write( "600*.10=60 blue<BR>\n" );
document.write( "600*.25=150 green<BR>\n" );
document.write( "600*.2=120 brown<BR>\n" );
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document.write( "B)<BR>\n" );
document.write( "1) 60/600 * 59/599 = .0098<BR>\n" );
document.write( "2) 90/600 = .15<BR>\n" );
document.write( "3) 60/600 * 150/599 = .0250<BR>\n" );
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document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );