document.write( "Question 378203: Find all the solutions between 0 and 2pi to the equation\r
\n" ); document.write( "\n" ); document.write( "cos(2x)=sin(x)+1
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Algebra.Com's Answer #268771 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Find all the solutions between 0 and 2pi to the equation
\n" ); document.write( "cos(2x)=sin(x)+1
\n" ); document.write( "\"cos+2%28theta%29\" = 1 - 2sin^2\"%28theta%29\"
\n" ); document.write( "1 - 2sin^2(x) = sin (x) + 1
\n" ); document.write( "2sin^2(x) + sin (x) =0
\n" ); document.write( "sin(x)[2sin(x) + 1] = 0
\n" ); document.write( "sin(x)=0
\n" ); document.write( "x = 0,\"pi\"
\n" ); document.write( "2sin(x) + 1 = 0
\n" ); document.write( "sin(x) = -1/2
\n" ); document.write( "x = 7/6 pi, 11/6 pi
\n" ); document.write( "(cos(x), sin(x))
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