document.write( "Question 378151: The outside of a picture frame measures 8in by 12in. 60^2 of the picture shows. Find the thickeness of the frame. \n" ); document.write( "
Algebra.Com's Answer #268713 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "The outside area would be
\n" ); document.write( "\"A=8%2A12=96\"
\n" ); document.write( "So the frame area is,
\n" ); document.write( "\"A%5Bf%5D=96-60=36\"
\n" ); document.write( "In terms of \"x\", the frame area is
\n" ); document.write( "\"A=2%288x%29%2B2%28x%2812-2x%29%29\"
\n" ); document.write( "\"A=16x%2B24x-4x%5E2\"
\n" ); document.write( "\"A=-4x%5E2%2B40x\"
\n" ); document.write( "Equate the two,
\n" ); document.write( "\"-4x%5E2%2B40x=36\"
\n" ); document.write( "\"x%5E2-10x%2B9=0\"
\n" ); document.write( "\"%28x-1%29%28x-9%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"x-1=0\"
\n" ); document.write( "\"highlight%28x=1%29\"
\n" ); document.write( "The second solution (x=9) would not make sense since the frame is only 8 inches wide.
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