document.write( "Question 378141: solve(3x)^2-12√(3x)+27=0 using the quadratic equation.\r
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document.write( "explain the steps please? \n" );
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Algebra.Com's Answer #268699 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! solve(3x)^2-12√(3x)+27=0 using the quadratic equation. \n" ); document.write( "----- \n" ); document.write( "It is not a quadratic the way you have posted it. \n" ); document.write( "---- \n" ); document.write( "The following would be the quadratic form: \n" ); document.write( "(3x)^2 - 12(3x) + 27 = 0 \n" ); document.write( "---- \n" ); document.write( "Letting w = 3x you get: \n" ); document.write( "w^2 - 12w + 27 = 0 \n" ); document.write( "(w-9)(w-3) = 0 \n" ); document.write( "w = 9 or w = 3 \n" ); document.write( "----- \n" ); document.write( "Solving for \"x\": \n" ); document.write( "3x=9 or 3x=3 \n" ); document.write( "x = 3 or x = 1 \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |