document.write( "Question 41592: simplify these expressions:\r
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\n" ); document.write( "\n" ); document.write( "the answer is supposed to be 2cosBsinB but i have no idea how that occurs.
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Algebra.Com's Answer #26869 by AnlytcPhil(1810)\"\" \"About 
You can put this solution on YOUR website!
Simplify these expressions:\r\n" );
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document.write( "   2cotB\r\n" );
document.write( "———————————\r\n" );
document.write( " 1 + cot²B\r\n" );
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document.write( "Use the identity cotq = cosq/sinq to replace\r\n" );
document.write( "the numerator\r\n" );
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document.write( "Use the identity 1 + cot²q = csc²q to replace \r\n" );
document.write( "the denominator\r\n" );
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document.write( "   2(cosB/sinB)\r\n" );
document.write( " ————————————————\r\n" );
document.write( "      csc²B\r\n" );
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document.write( "Use identity cscq = 1/sinq to replace denominator\r\n" );
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document.write( "   2(cosB/sinB)\r\n" );
document.write( " ————————————————\r\n" );
document.write( "     (1/sinB)²\r\n" );
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document.write( "   2cosB/sinB \r\n" );
document.write( " ————————————————\r\n" );
document.write( "     1/sin²B\r\n" );
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document.write( " 2cosB       1\r\n" );
document.write( "——————— ÷ ———————\r\n" );
document.write( " sinB      sin²B\r\n" );
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document.write( "Invert and multiply\r\n" );
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document.write( " 2cosB     sin²B\r\n" );
document.write( "——————— × ———————\r\n" );
document.write( " sinB        1\r\n" );
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document.write( "Cancel the sinB into the sin²B\r\n" );
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document.write( "           sinB  \r\n" );
document.write( " 2cosB     sin²B\r\n" );
document.write( "——————— × ———————\r\n" );
document.write( " sinB        1\r\n" );
document.write( "  1 \r\n" );
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document.write( "    2cosBsinB\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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