document.write( "Question 378128: two tears ago, Anton was three times as old as his sister, Nathalie. in 4 years, he will be only twice his sister's age. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #268658 by mananth(16946)![]() ![]() You can put this solution on YOUR website! two years ago, Anton was three times as old as his sister, Nathalie. in 4 years, he will be only twice his sister's age. find their present ages. \n" ); document.write( "... \n" ); document.write( "let Nathalie's age 2 years ago be x \n" ); document.write( "Anton 2 years ago was 3x \n" ); document.write( "... \n" ); document.write( "In 4 years \n" ); document.write( "Nathalie's age = x+6 \n" ); document.write( "Anton 's age = 3x+6 \n" ); document.write( ".. \n" ); document.write( "3x+6 = 2(x+6) \n" ); document.write( "3x+6 = 2x+12 \n" ); document.write( "3x-2x = 12-6 \n" ); document.write( "x= 6 Nathalie's age 2 years ago. So now she will be 8 years \n" ); document.write( "Anton was 3x years 2 years ago = 3*6 =18 \n" ); document.write( "so Now he is 18+2 = 20 years \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |