document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377988>Question 377988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i solve the following problem by using substitution method?<BR>\n" );
document.write( "2x-y=16<BR>\n" );
document.write( "-x+2y=-8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268638 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the top eq'n: y = 2x - 16.  Substitute into the bottom equation, to get<BR>\n" );
document.write( "-x + 2(2x - 16) = -8;<BR>\n" );
document.write( "-x + 4x - 32 = -8;<BR>\n" );
document.write( "3x = 24;<BR>\n" );
document.write( "x = 8.  Then y = 2*8- 16 = 0. </SPAN>\n" );
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