document.write( "Question 378046: If 10^2x=25, what is the value of 10^-x? \n" ); document.write( "
Algebra.Com's Answer #268636 by robertb(5830)\"\" \"About 
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\"10%5E%282x%29+=+25\". Take square roots of both sides to get \"10%5Ex+=+5\". (Discard \"10%5Ex+=+-5\" since the left-hand side is never negative.) THEN \"10%5E%28-x%29+=+1%2F5\", by taking reciprocals. \n" ); document.write( "
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