document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378107>Question 378107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" src=\"http://img221.imageshack.us/img221/5731/eq10.jpg\"> </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268628 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)  Add corresponding sides of the equations: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+=+10 ALIGN=MIDDLE  ALT=\"2x%5E2+=+10\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+=+5 ALIGN=MIDDLE  ALT=\"x%5E2+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Substituting this into the top equation, we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2+=+4 ALIGN=MIDDLE  ALT=\"y%5E2+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Thus there are 4 solutions: (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-sqrt%285%29 ALIGN=MIDDLE  ALT=\"-sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, -2), (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-sqrt%285%29 ALIGN=MIDDLE  ALT=\"-sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, 2), (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%285%29 ALIGN=MIDDLE  ALT=\"sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, -2), (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%285%29 ALIGN=MIDDLE  ALT=\"sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, 2).  (They represent the intersection points of a circle centered at (0,0) with radius 3 and a hyperbola with transverse axis  corresponding to the x-axis.)\r<BR>\n" );
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document.write( "2)Multiply the top eq'n by 2, and then add corresponding sides: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x%5E2+=+72 ALIGN=MIDDLE  ALT=\"8x%5E2+=+72\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+=+9 ALIGN=MIDDLE  ALT=\"x%5E2+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Substituting into the lower eq'n, we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16y%5E3+=+-2 ALIGN=MIDDLE  ALT=\"16y%5E3+=+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E3+=+-1%2F8 ALIGN=MIDDLE  ALT=\"y%5E3+=+-1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or y = -1/2.  Thus there are 2 solutions: (-3, -1/2) and (3, -1/2).\r<BR>\n" );
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document.write( "3)  Multiply the top eq'n by 2, and then add corresponding sides: 1/y = 3, or y = 1/3.  Substituting into the top eq'n, we get: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Fx+-9+=+1 ALIGN=MIDDLE  ALT=\"2%2Fx+-9+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Fx+=+10 ALIGN=MIDDLE  ALT=\"2%2Fx+=+10\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or x = 1/5. </SPAN>\n" );
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