document.write( "Question 378012: With a tailwind, a jet flew 2000 miles in 4 hours. The jets return trip against the same wind required 5 hours.
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document.write( "Find the jets speed and the wind speed. \n" );
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Algebra.Com's Answer #268625 by mananth(16946)![]() ![]() You can put this solution on YOUR website! With a tailwind, a jet flew 2000 miles in 4 hours. The jets return trip against the same wind required 5 hours. \n" ); document.write( "Find the jets speed and the wind speed. \n" ); document.write( ".. \n" ); document.write( "plane speed = xmph \n" ); document.write( "current speed = y mph \n" ); document.write( ".. \n" ); document.write( "with tailwind speed = x+y \n" ); document.write( "against wind speed = x-y \n" ); document.write( ".. \n" ); document.write( "2000/(x+y)=4 \n" ); document.write( "4(x+y)=2000 \n" ); document.write( "4x+4y=2000 \n" ); document.write( "/4 \n" ); document.write( "x+y =500 ......................1 \n" ); document.write( "... \n" ); document.write( "2000/(x-y)=5 \n" ); document.write( "5(x-y)=2000 \n" ); document.write( "5x-5y = 2000 \n" ); document.write( "/5 \n" ); document.write( "x-y = 400......................2 \n" ); document.write( "add 1 & 2 \n" ); document.write( "2x=900 \n" ); document.write( "/2 \n" ); document.write( "x= 450 mph .... speed of plane in still air \n" ); document.write( ".. \n" ); document.write( "x+y =500 \n" ); document.write( "x+450=500 \n" ); document.write( "x=500-450 \n" ); document.write( "x=50 mph ... speed of wind \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |