document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41591>Question 41591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> it say to use the substitutuon<BR>\n" );
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document.write( "y=x+2<BR>\n" );
document.write( "2x+y=8\r<BR>\n" );
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document.write( "x+y=3<BR>\n" );
document.write( "3x+y=3\r<BR>\n" );
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document.write( "3x-y=9<BR>\n" );
document.write( "2x+y=6\r<BR>\n" );
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document.write( "I hope you ca help I need to know how to do this for my examine </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26862 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=x+2<BR>\n" );
document.write( "2x+y=8<BR>\n" );
document.write( "Look at the first equation. (y = x + 2)-- <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" > has a solutions of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+2 ALIGN=MIDDLE  ALT=\"x+%2B+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2x + y = 8<BR>\n" );
document.write( "2x + x + 2 = 8<BR>\n" );
document.write( "3x = 6<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "So ....<BR>\n" );
document.write( "y = x + 2<BR>\n" );
document.write( "y = 2 + 2<BR>\n" );
document.write( "y = 4<BR>\n" );
document.write( "(2,4) is your solution! That is where the two line's meet.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+x%2B2%2C+-2x%2B8%29+ ALIGN=MIDDLE  ALT=\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+x%2B2%2C+-2x%2B8%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "x+y=3<BR>\n" );
document.write( "3x+y=3<BR>\n" );
document.write( "Change the first equation to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-x+%2B+3 ALIGN=MIDDLE  ALT=\"y+=+-x+%2B+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > by subtracting <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" > is equal to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-x+%2B+3 ALIGN=MIDDLE  ALT=\"-x+%2B+3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "3x + y = 3<BR>\n" );
document.write( "3x + -x + 3 = 3<BR>\n" );
document.write( "2x = 0<BR>\n" );
document.write( "x = 0<BR>\n" );
document.write( "So ....<BR>\n" );
document.write( "x + y = 3<BR>\n" );
document.write( "0 + y = 3<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "(0,3) is your solution! That is where the two line's meet.<BR>\n" );
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document.write( "3x-y=9<BR>\n" );
document.write( "2x+y=6<BR>\n" );
document.write( "Change the second equation to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-2x+%2B+6 ALIGN=MIDDLE  ALT=\"y+=+-2x+%2B+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > by subtracting <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x ALIGN=MIDDLE  ALT=\"2x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" > is equal to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2x+%2B+6 ALIGN=MIDDLE  ALT=\"-2x+%2B+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "3x - y = 9<BR>\n" );
document.write( "3x - (-2x + 6) = 9<BR>\n" );
document.write( "3x + 2x - 6 = 9<BR>\n" );
document.write( "5x = 15<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "So ....<BR>\n" );
document.write( "2x + y = 6<BR>\n" );
document.write( "2(3) + y = 6<BR>\n" );
document.write( "6 + y = 6<BR>\n" );
document.write( "y = 0<BR>\n" );
document.write( "(3,0) is your solution! That is where the two line's meet.<BR>\n" );
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