document.write( "Question 378057: Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability.\r
\n" ); document.write( "\n" ); document.write( "μ = 110; σ = 14\r
\n" ); document.write( "\n" ); document.write( "P(x ≥ 120) =
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Algebra.Com's Answer #268616 by robertb(5830)\"\" \"About 
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\"P%28X+%3E=+120%29+=+P%28%28X+-+110%29%2F14+%3E=+%28120+-+110%29%2F14+=+10%2F14+=+0.714%29\". Hence \"P%28X+%3E=+120%29+=+P%28Z+%3E=+0.714%29+=+0.2374\", approximately. \n" ); document.write( "
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