document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378060>Question 378060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find z such that 94.7% of the standard normal curve lies to the right of z. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268593 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well...this appears to be a pure statistics problem; even though I have never taken a statistics class, one possible way to solve it is to construct a definite integral with bounds from negative infinity to z. If there is a simple expression for the integral of the normal curve given by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2Fsqrt%282pi%29%29e%5E%28%28-x%5E2%29%2F2%29 ALIGN=MIDDLE  ALT=\"%281%2Fsqrt%282pi%29%29e%5E%28%28-x%5E2%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > (this is the expression I have seen for the normal distribution) then z can be easily found, using basic theorems from calculus. </SPAN>\n" );
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