document.write( "Question 378058: A man is nine times as old as his son. In nine years, he will be only three times as old as his son. How old are each now?
\n" ); document.write( "Solve using elimination method.
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Algebra.Com's Answer #268591 by mananth(16946)\"\" \"About 
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let son be x years
\n" ); document.write( "father = y
\n" ); document.write( "...
\n" ); document.write( "y=9x
\n" ); document.write( "after 3 years
\n" ); document.write( "son = x+9
\n" ); document.write( "father = y+9
\n" ); document.write( "(y+9)=3(x+9)
\n" ); document.write( "plug value of y =9x
\n" ); document.write( "(9x+9)=3x+27
\n" ); document.write( "9x+9=3x+27
\n" ); document.write( "-3x
\n" ); document.write( "9x-3x+9=27
\n" ); document.write( "6x+9=27
\n" ); document.write( "-9
\n" ); document.write( "6x=18
\n" ); document.write( "/6
\n" ); document.write( "x=3 son's age now
\n" ); document.write( "father's age = 9x = 27 years now
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca
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