document.write( "Question 378058: A man is nine times as old as his son. In nine years, he will be only three times as old as his son. How old are each now?
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document.write( "Solve using elimination method. \n" );
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Algebra.Com's Answer #268591 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let son be x years \n" ); document.write( "father = y \n" ); document.write( "... \n" ); document.write( "y=9x \n" ); document.write( "after 3 years \n" ); document.write( "son = x+9 \n" ); document.write( "father = y+9 \n" ); document.write( "(y+9)=3(x+9) \n" ); document.write( "plug value of y =9x \n" ); document.write( "(9x+9)=3x+27 \n" ); document.write( "9x+9=3x+27 \n" ); document.write( "-3x \n" ); document.write( "9x-3x+9=27 \n" ); document.write( "6x+9=27 \n" ); document.write( "-9 \n" ); document.write( "6x=18 \n" ); document.write( "/6 \n" ); document.write( "x=3 son's age now \n" ); document.write( "father's age = 9x = 27 years now \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |