document.write( "Question 377996: It takes Cathy 1.5 hours to paddle her canoe 6 miles upstream. Then she turns her canoe around and paddles 6 miles downstream in 1 hour.
\n" ); document.write( "What is the rate of the current?
\n" ); document.write( "What is Cathys paddling rate in still water?
\n" ); document.write( "

Algebra.Com's Answer #268546 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
It takes Cathy 1.5 hours to paddle her canoe 6 miles upstream. Then she turns her canoe around and paddles 6 miles downstream in 1 hour.
\n" ); document.write( "What is the rate of the current?
\n" ); document.write( "What is Cathys paddling rate in still water?
\n" ); document.write( "------------------------
\n" ); document.write( "Upstream DATA:
\n" ); document.write( "time = 1.5 hrs ; distance = 6 miles ; rate = 6/1.5 = 4 mph
\n" ); document.write( "---------------
\n" ); document.write( "Downstream DATA:
\n" ); document.write( "time = 1 hr ; distance = 6 miles ; rate = 6 mph
\n" ); document.write( "--------------------------
\n" ); document.write( "Equations:
\n" ); document.write( "Let current rate be \"c\"
\n" ); document.write( "Let rate in still water be \"w\"
\n" ); document.write( "----
\n" ); document.write( "w + c = 6
\n" ); document.write( "w - c = 4
\n" ); document.write( "------
\n" ); document.write( "Add and solve for \"w\":
\n" ); document.write( "2w = 10
\n" ); document.write( "w = 5 mph (paddling rate in still water)
\n" ); document.write( "----
\n" ); document.write( "Since w+c = 6, c = 1 mph (rate of the current)
\n" ); document.write( "===================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.
\n" ); document.write( "
\n" );