document.write( "Question 377996: It takes Cathy 1.5 hours to paddle her canoe 6 miles upstream. Then she turns her canoe around and paddles 6 miles downstream in 1 hour.
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document.write( "What is the rate of the current?
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document.write( "What is Cathys paddling rate in still water? \n" );
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Algebra.Com's Answer #268546 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! It takes Cathy 1.5 hours to paddle her canoe 6 miles upstream. Then she turns her canoe around and paddles 6 miles downstream in 1 hour. \n" ); document.write( "What is the rate of the current? \n" ); document.write( "What is Cathys paddling rate in still water? \n" ); document.write( "------------------------ \n" ); document.write( "Upstream DATA: \n" ); document.write( "time = 1.5 hrs ; distance = 6 miles ; rate = 6/1.5 = 4 mph \n" ); document.write( "--------------- \n" ); document.write( "Downstream DATA: \n" ); document.write( "time = 1 hr ; distance = 6 miles ; rate = 6 mph \n" ); document.write( "-------------------------- \n" ); document.write( "Equations: \n" ); document.write( "Let current rate be \"c\" \n" ); document.write( "Let rate in still water be \"w\" \n" ); document.write( "---- \n" ); document.write( "w + c = 6 \n" ); document.write( "w - c = 4 \n" ); document.write( "------ \n" ); document.write( "Add and solve for \"w\": \n" ); document.write( "2w = 10 \n" ); document.write( "w = 5 mph (paddling rate in still water) \n" ); document.write( "---- \n" ); document.write( "Since w+c = 6, c = 1 mph (rate of the current) \n" ); document.write( "=================================================== \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( " |