document.write( "Question 377975: The question is :
\n" ); document.write( "For i = the square root of -1, if 3i (2 + 5i) = x + 6i, then x = ?\r
\n" ); document.write( "\n" ); document.write( "I came up with x = 15, however, the test answer says x = -15. I am confused...how can you get the square root of a negative # and it be a negative #?
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Algebra.Com's Answer #268544 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
\"3i%282+%2B+5i%29\" simplifies to \"6i+%2B+15i%5E2\" or \"-15+%2B+6i\" --> x = -15.\r
\n" ); document.write( "\n" ); document.write( "The square root of a negative number is not defined on the real axis. This is why mathematicians created the number \"i+=+sqrt%28-1%29\". For example, \"sqrt%28-9%29+=+3i\".
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